Solving Equation with Brackets


 
 
Concept Explanation
 

Solving Equation with Brackets

Solving Equation with Brackets:

There are situations in which both the sides of an equation contain both variable (unknown quantity) and constant (numerals). In such cases, we first simplify two sides to their simplest forms and then transpose (shift) terms containing variable on R.H,S to L.H.S and constant terms on L.H.S and R.H.S By transposing a term form one side to other side, we mean changing its sign and carrying it to the other side. In transposition the plus sign of the term changs into minus sign on oher side and vice-versa.

The transposition method involves the following steps:

Step I  Obtain the linear euation.

Step II  Identify the variable (unknown quantity) and constants (numerals).

Step III  Simplify the L.H.S and R.H.S to their simplest forms by removing brackets.

Step IV  Transpose all terms containing variable on L.H.S and constant terms on R.H.S Note that the sign of the terms will change in shifting then form L.H.S to R.H.S and vice-versa.

Step V  SImplify L.H.S and R.H.S in the simplest form so that each side contains just one term.

Step VI  Solve the equation obtaineed in step V by dividing both sides by the coefficient of the variable on L.H.S

Example:  Solve: large frac{x+2}{6}-left [ frac{11-x}{3}-frac{1}{4}right ]=frac{3x-4}{12}

Solution    We have,

                         large frac{x+2}{6}-left [ frac{11-x}{3}-frac{1}{4}right ]=frac{3x-4}{12}

The denominators on two sides of the given equation are 6, 3, 4 and 12.

Their LCM is 12. Multiplying both sides of the given equaton by 12, we get

    large 12left (frac{x+2}{6} right )-12left ( frac{11-x}{3}-frac{1}{4} right )=12left ( frac{3x-4}{12} right )

large Rightarrow ;;2(x+2)-4(11-x)+12times frac{1}{4}=(3x-4)

large Rightarrow ;;2x+4-44+4x+3=3x-4

large Rightarrow ;;6x-37=3x-4

large Rightarrow ;;6x-3x=37-4                [Transposing 3x to LHS and -37 to RHS]

large Rightarrow ;;3x=33

Rightarrow ;;x=frac{33}{3}                                                    [Dividing both sides by 3]

Rightarrow ;;x=11

Check    Subtituting x = 11 on both sides of the given equation, we get

              L.H.S.=frac{x+2}{6}-left ( frac{11-x}{3}-frac{1}{4} right )

                      =frac{11+2}{6}-left ( frac{11-11}{3}-frac{1}{4} right )=frac{13}{6}-left ( 0-frac{1}{4} right )=frac{13}{6}+frac{1}{4}=frac{26+3}{12}=frac{29}{12}

 and ;;R.H.S.=frac{3x-4}{12}=frac{3times 11-4}{12}=frac{33-4}{12}=frac{29}{12}

Thus, for x = 11, we have L.H.S = R.H.S

Sample Questions
(More Questions for each concept available in Login)
Question : 1

Find the value of t:  large 6-2left ( 3-t right )=8

Right Option : C
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Explanation
Question : 2

-3left ( 3-x right )=12

Right Option : D
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Explanation
Question : 3

large dpi{80} 3left ( x+2 right )+2left ( 4x-1 right )=17

Right Option : C
View Explanation
Explanation
 
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